Если длина волейбольного поля 18м, а ширина составляет 1/2 часть длины, найдите периметр поля

sin150<span>°</span>+sin75<span>°</span>=sin(180<span>°</span>-150<span>°</span>)+sin(30<span>°</span>+45<span>°</span>)= -sin30<span>°</span>+sin30<span>°*cos45<span>°+sin45<span>°*cos30<span>°= -1/2+ 1/2* <span>√2/2+ <span>√2/2*<span>√3/2= -1/2+<span>√2/4+<span>√6/4=(<span>√2+<span>√6-2)/4=<span>√2(1+<span>√3-<span>√2)/4</span></span></span></span></span></span></span></span></span></span></span></span></span></span>

<span><span><span><span><span><span><span><span><span><span><span><span><span><span>Ну как-то так</span></span></span></span></span></span></span></span></span></span></span></span></span></span>