x² + 3x - 7 = 0;
x₁ + x₂ = -3; x₁ · x₂ = -7
x² + px + q = 0;
x'₁ = x₁ + 1; x'₂ = x₂ + 1
p = -(x'₁ + x'₂) = -(x₁ + 1 + x₂ + 1) = -(x₁ + x₂ + 2) = -(-3 + 2) = 1;
q = x'₁·x'₂ = (x₁ + 1)(x₂ + 1) = x₁ · x₂ + x₁ + x₂ + 1 = -7 - 3 + 1 = -9
Отже, x² + x - 9 = 0 - шукане рівняння.
<span>1/40=9
========
9*40=360
</span>
5х-6<3х+8
5х-3х<6+8
2х<14
х<14:2
х<7
Ответ: (-бесконечности, до 7).
M-5/12m=1/4
4*(m-5)=12m
4m-20=12m
4m-12m=20
-8m=20
m=-2,5