1)x1+x2=(1+√3+1-√3)/2=1
x1*x2=(1-3)/2=-1/2
x²-x-1/2=0
2x²-2x-1=0
2)<span>((a)-(bc/b-c))÷((b)-(ac/a-c))=(ab-ac-bc)/(b-c)*(a-c)/(ab-bc-ac)=(a-c)/(b-c)
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<em><span>Сумма квадратов диагоналей параллелограмма равна удвоенной сумме квадратов его сторон</span></em>
<span>2а²+2b²=d₁²+d₂²</span>
<span>2*10²+2*14²=20²+d²</span>
<span>200+392=400+d²</span>
<span>200+392-400=d²</span>
<span>d²=192</span>
<span>d=√192</span>
d=8√3
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