Востановить функцию по графикуf(x) =? ​

1/2*х+1/2-2х=5
-1,5х=4,5
х=-3
Между -4 и -2

Решение:
(2sinХ-Sin2X)/((2sinХ+Sin2X) = (2sinx-2SinXCosX)/(2sinx+2SinXCosX) =
2sinx(1-cosx)/2sinx(1+cosX) = (1-cos(2x/2))/(1+cos(2x/2)) =
(1-cos^2(x/2)+sin^2(x/2))/(1+cos^2(x/2)-sin^2(x/2)) =
<span>2sin^2(x/2)/2cos^2(x/2) = tg^2(x/2)</span>

(1/2+1/3)•2

3+2/6 = 5/6
5/6 * 2 = 5/3

(1/2-1/3)•3

3-2/6 = 1/6
1/6 * 3 = 1/2

3) 4) 1) 2) 5)
287+39-611:472*3-24=
1)611:472

А) 13, 12, 11, 10, 9.
б) 12, 11, 10, 9, 8.